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Divide each term in √2sin(x)=−1 2 sin ( x ) = - 1 by √2 2 and simplify.
www.mathway.comThe period of the sin(x) sin ( x ) function is 2π 2 π so values will repeat every 2π 2 π radians in both directions.
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17 авг. 2013 г. ... 5 Answers 5 ... Using that sin2x+cos2x=1; obtain a quadratic in sinx. ... Notice that since −1≤cosx≤1 and −1≤sinx≤1 we can see that cos2x≥0 ...
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www.mathway.comYou can put this solution on YOUR website! solve for sin(x): 2sinx -1 = 0 2sinx = 1 sinx = 1/2 Draw a 30,60,90 triangle. This means positive values in these quadrants: Q1 = All Q2 = Sin Q3 = Tangent Q4 = Cosine We want to know positive 1/2, so in Q1 and Q2 we have positive sin.
www.algebra.com11 сент. 2016 г. ... x=npi+(-1)^npi/6, where n is an integer. As 2sinx-1=0 2sinx=1 or sinx=1/2=sin(pi/6) Now as sine function is positive in first and second ... You can put this solution on YOUR website! solve for sin(x): 2sinx -1 = 0 2sinx = 1 sinx = 1/2 Draw a 30,60,90 triangle. This means positive values in these quadrants: Q1 = All Q2 = Sin Q3 = Tangent Q4 = Cosine We want to know positive 1/2, so in Q1 and Q2 we have positive sin.
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27 мая 2016 г. ... x = (11pi)/6, (7pi)/6 To solve this equation, go about it as you would any other equation. Get the sin x all by itself. 2 sin x +1 = 0 2 sin ...
socratic.org31 мар. 2019 г. ... Answer: 5pi/2 is a solution for the equation 2sin²x -sin x -1=0 Step-by-step explanation: We need to check 5pi/2 is a solution for the ...
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If any individual factor on the left side of the equation is equal to 0 0 , the entire expression will be equal to 0 0 . 2sin(x)−1=0 2 sin ( x ) - 1 = 0.
www.mathway.com27 апр. 2018 г. ... x = pi/2 + 2pin, {7pi}/6 + 2pin, {11pi}/6 + 2pin 2sin^2x - sinx - 1 = 0 Treat the equation as a quadratic equation. (2sinx + 1)(sinx - 1) ...
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